奇安信攻防社区-那CTF，那VMre，那些事（三）

那CTF，那VMre，那些事（三）

本篇文章为虚拟机保护re系列文章的第三篇，主要研究存在栈结构的虚拟机保护re的特点与解题步骤

0x01 前言
=======

本篇文章为虚拟机保护re系列文章的第三篇，主要研究存在栈结构的虚拟机保护re的特点

0x02 初探栈虚拟机
===========

学习栈虚拟机之前，我们不如先来了解一下虚拟机保护技术的分类以及栈虚拟机的特点。

> 虚拟机（CPU）的体系架构可分为3种，基于堆栈的(Stack based)，基于寄存器的(Register based)和3地址机器。我们只讲述基于堆栈的虚拟机架构(Stack based)；这种架构的虚拟机需要频繁操作堆栈，其使用的虚拟寄存器(虚拟的eax、ebx等等)保存在堆栈中；每个原子指令的handler都需要push、pop。

ctf re比赛中通常的`.exe`程序，一般是是基于寄存器的结构，堆栈一般只在函数传递参数时使用。而在vm保护中用来替代所保护程序的程序，则是基于堆栈的虚拟机架构。所以，在我们还原`case`,还原`handler`或者在还原程序逻辑的时候，**要始终贯彻用栈操作的思想**。

既然使用栈操作，肯定就少不了汇编的常用指令(push pop add sub jmp 等)下面我们先看一下，在存在堆栈结构的虚拟机保护题目当中，我们常用的汇编指令是如何实现的:

```php
Vadd:                            ;virtual add
        Mov eax,[esp+4]          ;取源操作数
        Mov ebx,[esp]            ;取目的操作数
        Add ebx,eax              ;
        Add esp,8                ;把参数从堆栈中删掉，平衡堆栈
        Push ebx                 ;把结果压入堆栈
      而原有的add命令的参数，我们需要翻译为 push 命令 。根据push 的对象不同，需要不同的实现：
vPushReg32:                      ;寄存器入栈 。esi指向字节码的内存地址
      Mov eax,dword ptr[esi]     ;从伪代码(字节码)中获得寄存器在VMcontext结构中的偏移地址
      Add esi,4                  ;VMcontext结构保存了各个寄存器的值。该结构保存在堆栈内。
      Mov eax,dowrd ptr [edi +eax]   ;得到寄存器的值。edi指向VMcontext结构的基址
      Push eax                    ;压入堆栈
      Jmp VMDispatcher            ;任务完成,跳回任务分派点
vPushImm32:                       ;立即数入栈
      Mov eax,dword ptr[esi]      ;字节码，不用翻译就是了
      Add esi,4
      Push eax                    ;立即数入栈
      Jmp VMDispatcher

vPopReg32:                       ;有Push指令了，也得有Pop指令：
      Mov eax,dword,ptr[esi]     ;从伪代码(字节码)中获得寄存器在VMcontext结构中的偏移地址
      Add esi,4
      Pop dword ptr [edi+eax]    ;弹回寄存器
      Jmp VMDispatcher
Add esi,eax
  转换为虚拟机的指令如下:
     vPushReg32 eax_index
     vPushReg32 esi_index
     Vadd
     vPopReg32 esi_index      ;不弹eax_index，它作为返回结果保存在堆栈里
Vjmp:
     Mov esi,dword ptr [esp]   ;jmp的参数在堆栈中
     Add esp,4                 ;平衡堆栈
     Jmp VMDispatcher
Vcall:
     Push all vreg            ;所有的虚拟的寄存器 (维护在堆栈中)
     Pop  all reg             ;弹出到真实的寄存器中(保存虚拟机的运行结果)
     Push 返回地址            ;可以让Call调用完成后，把控制权归还给虚拟机。
     Push 要调用的函数地址
     Retn
```

只看栈虚拟机各汇编指令的实现可能还不太形象。接下来我们比较一下基于堆栈虚拟机和基于寄存器虚拟机的区别。

一个基于Stack的虚拟机会通过IP来获取操作数，其操作数都是保存在Stack数据结构中，从栈中取出数据、计算然后再将结果存入栈中（LIFO，Last in first out）。

```php
   1、POP 20
   2、POP 7
   3、ADD 20, 7, result
   4、PUSH result
```

![image-20220219205252893](https://shs3.b.qianxin.com/attack_forum/2022/02/attach-a0eb946fa65b276d48fdac6e9e83cc92cf87e147.png)

而基于寄存器的虚拟机，它们的操作数是存放在CPU的寄存器的。没有入栈和出栈的操作和概念。但是执行的指令就需要包含操作数的地址了，也就是说，指令必须明确的包含操作数的地址，这不像栈可以用栈指针去操作。比如如下的加法操作： **ADD R1, R2, R3** ;就一条指令搞定了。不像**Stack-Based**一样，需要明确的制定操作数R1、R2、R3（这些都是寄存器）的地址。这种设计的优点就是去掉了入栈和出栈的操作，并且指令在寄存器虚拟机执行得更快。

![image-20220219205404131](https://shs3.b.qianxin.com/attack_forum/2022/02/attach-f3d3b42406d7765037369943bdd49871b0978a07.png)

初步了解了栈结构的虚拟机保护原理，我们来看几道ctf题目，从实战中加深理解

0x03 hgame-week4-easyvm
=======================

main函数逻辑非常简单：**输入一个字符串，然后初始化一个大数组，接下来执行sub\_1400017D0（不顺眼可以改个名）函数，最后与一个已知数组进行匹配判定**为节省篇幅这里放反编译main函数的伪代码

```2
int __cdecl main(int argc, const char **argv, const char **envp)
{
  __int64 v3; // rcx
  __int64 v5[124]; // [rsp+20h] [rbp-E0h] BYREF
  int v6[6]; // [rsp+400h] [rbp+300h] BYREF
  char v7; // [rsp+418h] [rbp+318h]
  __int64 v8[5]; // [rsp+420h] [rbp+320h] BYREF
  char v9; // [rsp+448h] [rbp+348h]

print("Input your flag: \n");
  v8[0] = 0i64;
  v8[1] = 0i64;
  v8[2] = 0i64;
  v8[3] = 0i64;
  v8[4] = 0i64;
  v9 = 0;
  scanf("%40s", (const char *)v8);
  v6[0] = 16909568;
  v5[0] = (__int64)v8;
  v6[1] = 83953669;
  v6[2] = 201657858;
  v6[3] = 100860676;
  v6[4] = 50792965;
  v6[5] = 184879105;
  v7 = 13;

#初始化大数组
  V5[1]=40i64
  V5[2]=1i64
  ......
  sub_1400017D0(v6, v5);
  v3 = 0i64;
  while ( *((_BYTE *)v8 + v3) == byte_140004000[v3] )
  {
    if ( ++v3 >= 40 )
      return 0;
  }
  print("error\n");
  return 0;
}
```

接下来跟进该关键函数

```php
__int64 __fastcall sub_1400017D0(__int64 a1, _QWORD *a2)
{
  __int64 v3; // rsi
  _QWORD *v4; // rdx
  bool v5; // zf
  _QWORD *v6; // rdx
  _QWORD *v7; // rdx
  __int64 v8; // rcx
  _QWORD *v9; // rdx
  __int64 v10; // rcx
  _QWORD *v11; // r8
  __int64 v13[3]; // [rsp+20h] [rbp-39h] BYREF
  __int64 v14; // [rsp+38h] [rbp-21h] BYREF
  __int64 v15[7]; // [rsp+40h] [rbp-19h] BYREF
  __int64 v16; // [rsp+78h] [rbp+1Fh]
  _QWORD *v17; // [rsp+80h] [rbp+27h]
  __int64 v18; // [rsp+88h] [rbp+2Fh]
  __int64 v19; // [rsp+90h] [rbp+37h] BYREF

v17 = a2;
  v3 = stack(200i64);# 构造栈
  v15[6] = a1;
  v16 = a1;
  v14 = 0i64;
  v15[0] = 0i64;
  v15[1] = 0i64;
  v15[2] = 0i64;
  v15[4] = 0i64;
  v15[3] = 0i64;
  v13[2] = 0i64;
  v18 = 0i64;
  if ( a1 )
  {
    while ( 2 )
    {
      switch ( *(_BYTE *)++v16 )
      {
        case 1:
          sub_1400010E0(v14, v3);
          goto LABEL_22;
        case 2:
          sub_1400010C0(&v14, v3);
          goto LABEL_22;
        case 3:
          sub_1400010E0(v15[0], v3);
          goto LABEL_22;
        case 4:
          sub_1400010C0(v15, v3);
          goto LABEL_22;
        case 5:
          sub_1400010E0(*v17++, v3);
          goto LABEL_22;
        case 6:
          v19 = 0i64;
          sub_1400010C0(&v19, v3);
          v10 = *(unsigned __int8 *)v19;
          v19 = v10;
          sub_1400010E0(v10, v3);
          goto LABEL_22;
        case 7:
          v19 = 0i64;
          v13[0] = 0i64;
          sub_1400010C0(&v19, v3);
          sub_1400010C0(v13, v3);
          *(_BYTE *)v13[0] = v19;
          goto LABEL_22;
        case 8:
          v19 = 0i64;
          sub_1400010C0(&v19, v3);
          v4 = (_QWORD *)(*(_QWORD *)(v3 + 16) + 8i64 * *(_QWORD *)(v3 + 8));
          *v4 += v19;
          v5 = *(_QWORD *)(*(_QWORD *)(v3 + 16) + 8i64 * *(_QWORD *)(v3 + 8)) == 0i64;
          LODWORD(v18) = 0;
          HIDWORD(v18) = v5;
          goto LABEL_22;
        case 9:
          v19 = 0i64;
          sub_1400010C0(&v19, v3);
          v6 = (_QWORD *)(*(_QWORD *)(v3 + 16) + 8i64 * *(_QWORD *)(v3 + 8));
          *v6 -= v19;
          HIDWORD(v18) = *(_QWORD *)(*(_QWORD *)(v3 + 16) + 8i64 * *(_QWORD *)(v3 + 8)) == 0i64;
          LODWORD(v18) = *(_DWORD *)(*(_QWORD *)(v3 + 16) + 8i64 * *(_QWORD *)(v3 + 8)) & 0x80000000;
          goto LABEL_22;
        case 0xA:
          v19 = 0i64;
          sub_1400010C0(&v19, v3);
          v7 = (_QWORD *)(*(_QWORD *)(v3 + 16) + 8i64 * *(_QWORD *)(v3 + 8));
          *v7 ^= v19;
          goto LABEL_22;
        case 0xB:
          v19 = 0i64;
          sub_1400010C0(&v19, v3);
          v16 += v19;
          goto LABEL_22;
        case 0xC:
          v19 = 0i64;
          sub_1400010C0(&v19, v3);
          if ( HIDWORD(v18) )
            v16 += v19;
          goto LABEL_22;
        case 0xD:
          free(*(void **)(v3 + 16));
          free((void *)v3);
          return 1i64;
        case 0xE:
          v9 = (_QWORD *)(*(_QWORD *)(v3 + 16) + 8i64 * *(_QWORD *)(v3 + 8));
          HIDWORD(v18) = *(v9 - 1) == *v9;
          goto LABEL_22;
        case 0xF:
          v11 = (_QWORD *)(*(_QWORD *)(v3 + 16) + 8i64 * *(_QWORD *)(v3 + 8));
          HIDWORD(v18) = *(v11 - 1) % *v11 == 0i64;
          goto LABEL_22;
        case 0x11:
          v19 = 0i64;
          sub_1400010C0(&v19, v3);
          v8 = -1i64;
          do
            ++v8;
          while ( *(_BYTE *)(v19 + v8) );
          sub_1400010E0(v8, v3);
          goto LABEL_22;
        case 0x12:
          DebugBreak();
          goto LABEL_22;
        default:
LABEL_22:
          if ( !v16 )
            return 0i64;
          continue;
      }
    }
  }
  return 0i64;
}
```

上述函数内存注释部分相当于构造了这么一个栈结构体

```php
struct StackInfo{
    QWORD Size; //栈尺寸
    QWORD CurrentStackTop; //栈顶
    QWORD pStack; // 指向分配出来的栈
}
```

静态分析分析不太出来内容了。我们采取动态调试的方法，动态调试发现函数的作用就是取出输入字符串中的每三个其中的第二个和未知固定值进行一次异或，共循环0x20次。

接下来我们使用ida-python导出数组，得到要异或的值。运行以下脚本再输入40个a

```php
from idc_bc695 import *
auto addr=0x7FF7889917D0; //函数处理后的位置
auto x,i;
for(i=0;i<48;i++){
    x=byte(addr);
    Message("0x%x,",x);
    addr=addr+1;
}
```

得到的值再和‘a’异或,获得要异或的值。

导出数组后写最终脚本

```php
cipher = [58, 84, 47, 42, 47, 54, 19, 1, 46, 3,
 53, 64, 71, 14, 95, 89, 1, 105, 39, 8,
  61, 76, 51, 26, 45, 11, 64, 14, 75, 36, 
  65, 39, 37, 40, 41, 42, 2, 2, 93, 36]
xor = [82, 51, 78, 71, 74, 77, 103, 105, 71, 112, 106, 54, 42, 81, 54, 42, 94, 54, 84, 103, 78, 35, 64, 117, 94, 100, 51, 97, 56, 75, 50, 72, 86, 71, 118, 79, 99, 113, 36, 89]
for i in range(40):
    print(chr(cipher[i] ^ xor[i]), end='')
```

得到flag：hgame{this\_vm\_is\_\_sosososososososo\_easy}

0x04 虎符ctf-vm
=============

题目的main函数比较简单（main函数比较简单的题一般都比较难吗？），只是调用了一个vm函数。vm函数就非常关键了。反编译一下

![image-20220220165831378](https://shs3.b.qianxin.com/attack_forum/2022/02/attach-89f0281c76c56c7f7c396b17600eb9f83361df23.png)

可以看出是比较典型的一个`while(1)`和`switch(opcode)`的结构做的虚拟机。

我们先分析一下声明的数据变量的含义

```php
vm_eip  偏移量，使用这个配合code地址检索opcode，opcode = *(&code + vm_eip)，
vm_sp： 代表栈内数据数量，也配合栈地址形成指向栈顶的指针，
code：  code源码
vm_stack：这个是这个栈堆机器操作的栈，
vm_arr： 一片内存空间，主要用于储存三个数组，一个预定义好了的arr1(在50-91)，一个用户输入的arr2(在100-141)，一个由arr2处理成的arr3(在0-41)，对arr的处理是重点
vm_block： 这个储存另一部分数据，主要是用于储存循环时的计数器，是一个python解释器中block_stack的地位，
```

接着我们分析一下各opcode的作用（ida注释yyds）

**对栈的基础操作：**

```php
opcode(0x1) ==> 0x1, ==> push input， 接收一个用户输入字节并压入栈中，
opcode(0x4) ==> 0x4, var, ==> push var;
opcode(0x7) ==> 0x7, index, ==> push vm_arr[index],
opcode(0x5) ==> 0x5, index, ==> push vm_block[index]
opcode(0x12) ==> 0x12, ==> vm_stack[vm_sp] = ~vm_stack[vm_sp] 对栈顶数值取反。
opcode(0x19) ==> 0x19, ==> vm_stack[vm_sp-1] = vm_arr[vm_stack[vm_sp-1]]，
```

运算，存储机制采用的是我们之前说过的堆栈机制。弹出栈顶两个，再把计算结果压栈

```php
opcode(9) ==> 9 ==> binary_add 加法 +
opcode(0xa) ==> 0xa ==> binary_subtract 减法-
opcode(0xb) ==> 0xb ==> binary_multiply乘法 ×
opcode(0xd) ==> 0xd ==> binary_modulo 取余 %
opcode(0xf) ==> 0xf ==> binary_and 按位与 &
opcode(0x10) ==> 0x10 ==> binary_or 按位或 |
```

**判断和跳转：**

```php
opcode(0x1d) ==> 0x1d, tar, ==>jump $+tar， 直接跳转到参数指定的位置，但是要注意，有时候这个参数其实是负数， 回跳，形成一个循环结构。

剩下几个都是，根据栈顶两个值的大小关系，决定是否跳转到指定位置:
opcode(0x18) ==> 0x18, tar, ==> if vm_stack[vm_sp] < vm_stack[vm_sp-1]: jump $+tar，
opcode(0x16) ==> 0x16, tar, ==> if vm_stack[vm_sp] > vm_stack[vm_sp-1]: jump $+tar，
opcode(0x14) ==> 0x14, tar, ==> if vm_stack[vm_sp] == vm_stack[vm_sp-1]: jump $+tar,
```

**对于数组的操作：**

```php
opcode(8) ==> 8, index, ==> vm_arr[index] = vm_stack[vm_sp];
opcode(0x1a) ==> 0x1a, ==> vm_arr[vm_stack[vm_sp]] = vm_stack[vm_sp-1]
```

**对于block的操作：**

```php
opcode(0x5) ==> 0x5, index, ==> push vm_block[index]
opcode(0x6) ==> 0x6, ==> vm_block[var] = vm_stack[vm_sp]
opcode(0x1c) ==> 0x1c, ==> vm_block[vm_stack[vm_sp]] = vm_stack[vm_sp-1]
```

**io：**

```php
opcode(0x2) ==> 0x2, ==> print vm_stack[vm_sp]打印栈顶的数值对应字符。
opcode(0x1) ==> 0x1, ==> push input， 接收一个用户输入字节并压入栈中，
```

**语句组合拳**

这个是看了dalaoWP才悟出的操作，有一些op\_code的字符构成了一些结构，我们需要注意。

```php
0x1 or 0x4 ->0x8 #压栈，然后将栈顶弹出到arr中，其实就相当于是向arr里面赋值，一开始大片的0x4 ->0x8 是赋值arr1, 接着就是0x1->0x8是初始化arr2
0x4-0x6
设置block内的值
0x5-0x4-0x16
判断block里的值和0x4参数的大小，在code中出现过三次，都是循环的开头部分
0x1D 参数为负数
0x1d 后面的参数有负数的情况，其实就是相当于减法，回跳，一般配合前面这个0x5-0x4-0x16，形成一个循环结构
```

关于字节码的分析，我是根据字节码所对应的汇编操作以及语句组合拳一点一点分析出来的。当然更高阶的玩法是写翻译字节码的脚本，笔者暂时整不明白，一会儿piao个大佬的脚本以供大家学习，我先写一写小白做法。

小白做法：根据op\_code手撕
-----------------

先简单讲一下手撕逻辑吧：

**arr1数组赋值初始化部分：**

```php
 0x04, 0x66, 0x08, 0x32
```

0x04 ... 0x08 0x32是一个完整的`arr1`数组一位的赋值语句。

**list读入部分：**

```php
0x01, 0x08, 0x64
0x01, 0x08, 0x65
0x01, 0x08, 0x66
......
0x01,0x08,0x8D
```

`arr2`是从`input`中读入的数据获取的，从0x64~0x8D一共读取了41位

**循环结构（就讲一个）：**

记得我们上文提到过的组合拳吗？

```php
0x5-0x4-0x16
```

来看某一个循环对应的opcode

```php
for j in range(7):
 0x05, 0x00, 0x04, 0x07,
```

再来看一个：

```php
for i in range(6):
0x05, 0x01, 0x04, 0x06
```

什么叫不言自明啊（战术后仰）相信明眼人已经都懂了qaq

**手撕大法好**

手撕撕了好久好久，在大佬博客的帮助下终于手撕出来了伪代码，下面是字节码和伪代码对应版

```python
# 0x04, 0x66, 0x08, 0x32, 0x04, 0x4E, 0x08, 0x33, 0x04, 0xA9, 0x08, 0x34, 0x04, 0xFD, 0x08, 0x35, 0x04, 0x3C, 0x08, 0x36, 0x04, 0x55, 0x08, 0x37, 0x04, 0x90, 0x08, 0x38, 0x04, 0x24, 0x08, 0x39, 0x04, 0x57, 0x08, 0x3A, 0x04, 0xF6, 0x08, 0x3B, 0x04, 0x5D, 0x08, 0x3C, 0x04, 0xB1, 0x08, 0x3D, 0x04, 0x01, 0x08, 0x3E, 0x04, 0x20, 0x08, 0x3F, 0x04, 0x81, 0x08, 0x40, 0x04, 0xFD, 0x08, 0x41, 0x04, 0x36, 0x08, 0x42, 0x04, 0xA9, 0x08, 0x43, 0x04, 0x1F, 0x08, 0x44, 0x04, 0xA1, 0x08, 0x45, 0x04, 0x0E, 0x08, 0x46, 0x04, 0x0D, 0x08, 0x47, 0x04, 0x80, 0x08, 0x48, 0x04, 0x8F, 0x08, 0x49, 0x04, 0xCE, 0x08, 0x4A, 0x04, 0x77, 0x08, 0x4B, 0x04, 0xE8, 0x08, 0x4C, 0x04, 0x23, 0x08, 0x4D, 0x04, 0x9E, 0x08, 0x4E, 0x04, 0x27, 0x08, 0x4F, 0x04, 0x60, 0x08, 0x50, 0x04, 0x2F, 0x08, 0x51, 0x04, 0xA5, 0x08, 0x52, 0x04, 0xCF, 0x08, 0x53, 0x04, 0x1B, 0x08, 0x54, 0x04, 0xBD, 0x08, 0x55, 0x04, 0x32, 0x08, 0x56, 0x04, 0xDB, 0x08, 0x57, 0x04, 0xFF, 0x08, 0x58, 0x04, 0x28, 0x08, 0x59, 0x04, 0xA4, 0x08, 0x5A, 0x04, 0x5D, 0x08, 0x5B, 
arr1 =  [102, 78, 169, 253, 60, 85, 144, 36, 87, 246, 93, 177, 1, 32, 129, 253, 54, 169, 31, 161, 14, 13, 128, 143, 206, 119, 232, 35, 158, 39, 96, 47, 165, 207, 27, 189, 50, 219, 255, 40, 164, 93]
# 0x01, 0x08, 0x64, 0x01, 0x08, 0x65, 0x01, 0x08, 0x66, 0x01, 0x08, 0x67, 0x01, 0x08, 0x68, 0x01, 0x08, 0x69, 0x01, 0x08, 0x6A, 0x01, 0x08, 0x6B, 0x01, 0x08, 0x6C, 0x01, 0x08, 0x6D, 0x01, 0x08, 0x6E, 0x01, 0x08, 0x6F, 0x01, 0x08, 0x70, 0x01, 0x08, 0x71, 0x01, 0x08, 0x72, 0x01, 0x08, 0x73, 0x01, 0x08, 0x74, 0x01, 0x08, 0x75, 0x01, 0x08, 0x76, 0x01, 0x08, 0x77, 0x01, 0x08, 0x78, 0x01, 0x08, 0x79, 0x01, 0x08, 0x7A, 0x01, 0x08, 0x7B, 0x01, 0x08, 0x7C, 0x01, 0x08, 0x7D, 0x01, 0x08, 0x7E, 0x01, 0x08, 0x7F, 0x01, 0x08, 0x80, 0x01, 0x08, 0x81, 0x01, 0x08, 0x82, 0x01, 0x08, 0x83, 0x01, 0x08, 0x84, 0x01, 0x08, 0x85, 0x01, 0x08, 0x86, 0x01, 0x08, 0x87, 0x01, 0x08, 0x88, 0x01, 0x08, 0x89, 0x01, 0x08, 0x8A, 0x01, 0x08, 0x8B, 0x01, 0x08, 0x8C, 0x01, 0x08, 0x8D, 
arr2 = list(input()) # len = 41
# 0x04, 0x00, 0x06, 0x00, 0x05, 0x00, 0x04, 0x07, 0x16, 0x56, 
var1 = 0 
for j in range(7):
# 0x04, 0x00, 0x06, 0x01, 0x05, 0x01, 0x04, 0x06, 0x16, 0x42, 
    for i in range(6):
        var1 = arr2[6*j+i]
        var1 = ~var1
        var1 &= (i + 2) * j
        var2 = arr2[6*j + i]
        var2 &= ~((i + 2) * j)
        var1 |= var2
        arr3[i * 7 + j] = var
for i in range(1, 42):
    # 0x05, 0x00, 0x04, 0x02, 0x0D, 0x04, 0x00, 0x14, 0x0F,
    if i % 2 == 0:
        # arr[i] += arr[i-1]
        # 注意还会进行高位舍去
        arr[i] = (arr[i] + arr[i - 1]) & 0xff
    # 0x05, 0x00, 0x19, 0x05, 0x00, 0x04, 0x01, 0x0A, 0x19, 0x09, 0x05, 0x00, 0x1A,
    # 0x05, 0x00, 0x04, 0x02, 0x0D, 0x04, 0x01, 0x14, 0x0B,
    if i % 2 == 1:
        arr[i] = (arr[i] * 0x6b) & 0xff
# 0x04, 0x6B, 0x05, 0x00, 0x19, 0x0B, 0x05, 0x00, 0x1A, 0x05, 0x00, 0x04, 0x01, 0x09, 0x04, 0x00, 0x1C, 0x1D, 0xCA,
for i in range(0x29):
    if arr[i] != arr1[i]:
        print('n')
        return 0
    print('y')
    return 0
```

手撕获得了伪代码，写脚本逆向就变成了多是一件美事~

大佬解法：翻译字节码脚本
------------

```python
class Translate():
    def opcode(self):
        '''
        得到一个字节码字典
        '''
        dic = r'''1    getchar()
2    pop a; printf(a)
3    vm_eip ++
4    push data
5    push d[data]
6    pop d[data]
7    push c[data]
8    pop c[data]
9    pop a; pop b; push b+a
0xa    pop a; pop b; push b-a
0xb    pop a; pop b; push b*a
0xc    pop a; pop b; push b/a
0xd    pop a; pop b; push b%a
0xe    pop a; pop b; push b^a
0xf    pop a; pop b; push b&a
0x10    pop a; pop b; push b|a
0x11    pop a; push -a;
0x12    pop a; push ~a;
0x13    pop a; pop b; if (b!=a) {vm_eip+=2} else {vm_eip+=data}
0x14    pop a; pop b; if (b==a) {vm_eip+=2} else {vm_eip+=data}
0x15    pop a; pop b; if (b<=a) {vm_eip+=2} else {vm_eip+=data}
0x16    pop a; pop b; if (b<a) {vm_eip+=2} else {vm_eip+=data}
0x17    pop a; pop b; if (b>=a) {vm_eip+=2} else {vm_eip+=data}
0x18    pop a; pop b; if (b>a) {vm_eip+=2} else {vm_eip+=data}
0x19    pop a; push c[a]
0x1a    pop a; pop b; c[a] = b
0x1b    pop a; push d[a]
0x1c    pop a; pop b; d[a] = b
0x1d    vm_eip += data; if (*vm_eip>0x1d) return vm_eip
0x1e    return vm_eip'''
        self.opcode_dict = {}
        for i in dic.split('\n'):
            num, opcode = int(i.split('\t')[0], 16), i.split('\t')[1]
            self.opcode_dict[num] = opcode

def translate_part_3_opcode(self):
        '''
        翻译字节码
        '''
        self.opcode()

with open(r'code', 'rb')as f:
            self.b = f.read()

eip = 0x126
        while eip < 0x1e8:
            op = self.b[eip]
            if 'data' in self.opcode_dict[op]:
                #将data替换为具体的操作数
                data = self.b[eip+1]
                print('{0:<8}{1:<5}{2:<7}{3}'.format(hex(eip), hex(op), hex(data), self.opcode_dict[op].replace('data', hex(data))))
                eip += 2
            else:
                print('{0:<8}{1:<12}{2}'.format(hex(eip), hex(op), self.opcode_dict[op]))
                eip += 1

def __init__(self):
        self.opcode()
        self.translate_part_3_opcode()

t = Translate()
```

这样的话可得到如下的伪汇编指令：

```php
0x126   0x4  0x0    push 0x0
0x128   0x6  0x0    pop d[0x0]

0x12a   0x5  0x0    push d[0x0]
0x12c   0x4  0x7    push 0x7
0x12e   0x16 0x56   pop a; pop b; cmp a,b; jbe 0x184;
0x130   0x4  0x0    push 0x0
0x132   0x6  0x1    pop d[0x1]

0x134   0x5  0x1    push d[0x1]
0x136   0x4  0x6    push 0x6
0x138   0x16 0x42   pop a; pop b; cmp a,b; jbe 0x17a;
0x13a   0x5  0x0    push d[0x0]
0x13c   0x4  0x6    push 0x6
0x13e   0xb         pop a; pop b; push b*a
0x13f   0x5  0x1    push d[0x1]
0x141   0x9         pop a; pop b; push b+a
0x142   0x4  0x64   push 0x64
0x144   0x9         pop a; pop b; push b+a
0x145   0x19        pop a; push c[a]
0x146   0x12        pop a; push ~a;
0x147   0x5  0x0    push d[0x0]
0x149   0x5  0x1    push d[0x1]
0x14b   0x4  0x2    push 0x2
0x14d   0x9         pop a; pop b; push b+a
0x14e   0xb         pop a; pop b; push b*a
0x14f   0xf         pop a; pop b; push b&a
0x150   0x4  0x64   push 0x64
0x152   0x5  0x0    push d[0x0]
0x154   0x4  0x6    push 0x6
0x156   0xb         pop a; pop b; push b*a
0x157   0x5  0x1    push d[0x1]
0x159   0x9         pop a; pop b; push b+a
0x15a   0x9         pop a; pop b; push b+a

0x15b   0x19        pop a; push c[a]
0x15c   0x5  0x0    push d[0x0]
0x15e   0x5  0x1    push d[0x1]
0x160   0x4  0x2    push 0x2
0x162   0x9         pop a; pop b; push b+a
0x163   0xb         pop a; pop b; push b*a
0x164   0x12        pop a; push ~a;
0x165   0xf         pop a; pop b; push b&a
0x166   0x10        pop a; pop b; push b|a
0x167   0x5  0x1    push d[0x1]
0x169   0x4  0x7    push 0x7
0x16b   0xb         pop a; pop b; push b*a
0x16c   0x5  0x0    push d[0x0]
0x16e   0x9         pop a; pop b; push b+a
0x16f   0x1a        pop a; pop b; c[a] = b
0x170   0x5  0x1    push d[0x1]
0x172   0x4  0x1    push 0x1
0x174   0x9         pop a; pop b; push b+a
0x175   0x4  0x1    push 0x1
0x177   0x1c        pop a; pop b; d[a] = b
0x178   0x1d 0xbc   jmp 0x134

0x17a   0x5  0x0    push d[0x0]
0x17c   0x4  0x1    push 0x1
0x17e   0x9         pop a; pop b; push b+a
0x17f   0x4  0x0    push 0x0
0x181   0x1c        pop a; pop b; d[a] = b
0x182   0x1d 0xa8   jmp 0x12a                                       
;以上为第一部分，二重循环。设输入为x，求出f(x)，存储在c[0]~c[0x29]

;第一个部分循环跳出至此
0x184   0x4  0x1    push 0x1                                        
0x186   0x6  0x0    pop d[0x0]

0x188   0x5  0x0    push d[0x0]
0x18a   0x4  0x2a   push 0x2a
0x18c   0x16 0x34   pop a; pop b; cmp a,b; jbe 0x1c0;
0x18e   0x5  0x0    push d[0x0]
0x190   0x4  0x2    push 0x2
0x192   0xd         pop a; pop b; push b%a
0x193   0x4  0x0    push 0x0
0x195   0x14 0xf    pop a; pop b; cmp a,b; jnz 0x1a4;
0x197   0x5  0x0    push d[0x0]
0x199   0x19        pop a; push c[a]
0x19a   0x5  0x0    push d[0x0]
0x19c   0x4  0x1    push 0x1
0x19e   0xa         pop a; pop b; push b-a
0x19f   0x19        pop a; push c[a]
0x1a0   0x9         pop a; pop b; push b+a
0x1a1   0x5  0x0    push d[0x0]
0x1a3   0x1a        pop a; pop b; c[a] = b

0x1a4   0x5  0x0    push d[0x0]
0x1a6   0x4  0x2    push 0x2
0x1a8   0xd         pop a; pop b; push b%a
0x1a9   0x4  0x1    push 0x1
0x1ab   0x14 0xb    pop a; pop b; cmp a,b; jnz 0x1b6;
0x1ad   0x4  0x6b   push 0x6b
0x1af   0x5  0x0    push d[0x0]
0x1b1   0x19        pop a; push c[a]
0x1b2   0xb         pop a; pop b; push b*a
0x1b3   0x5  0x0    push d[0x0]
0x1b5   0x1a        pop a; pop b; c[a] = b

0x1b6   0x5  0x0    push d[0x0]
0x1b8   0x4  0x1    push 0x1
0x1ba   0x9         pop a; pop b; push b+a
0x1bb   0x4  0x0    push 0x0
0x1bd   0x1c        pop a; pop b; d[a] = b
0x1be   0x1d 0xca   jmp 0x188                                       
;至此为第二部分，按照下标的奇偶，分别将上一步得到的数据进一步加密

;以下为第三部分，判断c[i]是否和c[i+0x32]是否相等，相等输出y，反之输出n
0x1c0   0x4  0x0    push 0x0                                        
0x1c2   0x6  0x0    pop d[0x0]

0x1c4   0x5  0x0    push d[0x0]
0x1c6   0x4  0x29   push 0x29
0x1c8   0x18 0x4    pop a; pop b; cmp a,b; jae 0x1cc;
0x1ca   0x1d 0x1b   jmp 0x1e5                                       
;jmp to printf('y')

0x1cc   0x5  0x0    push d[0x0]
0x1ce   0x19        pop a; push c[a]
0x1cf   0x4  0x32   push 0x32
0x1d1   0x5  0x0    push d[0x0]
0x1d3   0x9         pop a; pop b; push b+a
0x1d4   0x19        pop a; push c[a]
0x1d5   0x14 0xc    pop a; pop b; cmp a,b; jnz 0x1e1;               
;jmp to printf('n')

0x1d7   0x5  0x0    push d[0x0]
0x1d9   0x4  0x1    push 0x1
0x1db   0x9         pop a; pop b; push b+a
0x1dc   0x4  0x0    push 0x0
0x1de   0x1c        pop a; pop b; d[a] = b
0x1df   0x1d 0xe5   jmp 0x1c4

0x1e1   0x4  0x6e   push 0x6e                                                
;printf('n')
0x1e3   0x2         pop a; printf(a)                                
0x1e4   0x1e        return vm_eip

;printf('y')
0x1e5   0x4  0x79   push 0x79
0x1e7   0x2         pop a; printf(a)                                
```

————————————————————————————————————————————————————————————

原文链接：<http://blog.iyzyi.com/index.php/archives/1252/>

作者：iyzyi

再将汇编翻译成伪代码就可以了，这个就得看你的汇编功底了，你只能靠你自己~

PS:关于如下部分的re
------------

```php
for j in range(7):
# 0x04, 0x00, 0x06, 0x01, 0x05, 0x01, 0x04, 0x06, 0x16, 0x42, 
    for i in range(6):
        var1 = arr2[6*j+i]
        var1 = ~var1
        var1 &= (i + 2) * j
        var2 = arr2[6*j + i]
        var2 &= ~((i + 2) * j)
        var1 |= var2
        arr3[i * 7 + j] = var
```

以上花里胡稍的操作， 其实就是个异或关系。即

```php
a ^ b = (~a & b) | (a & ~b)
```

附解题脚本

```php
arr1 =  [102, 78, 169, 253, 60, 85, 144, 36, 87, 246, 93, 177, 1, 32, 129, 253, 54, 169, 31, 161, 14, 13, 128, 143, 206, 119, 232, 35, 158, 39, 96, 47, 165, 207, 27, 189, 50, 219, 255, 40, 164, 93]
arr = [0] * 42
arr[0] = arr1[0]
flag = ''

for i in range(1, 42):
    if i % 2 ==0:
        arr[i] = (arr1[i] - arr1[i-1]) & 0xff
    if i % 2 ==1:   
        for j in range(0xff):
            if (j * 0x6b) & 0xff == arr1[i]:
                arr[i] = j

for j in range(7):
    for i in range(6):
        flag += chr(arr[i * 7+j] ^ ((i + 2) * j))

print(flag)
```

0x05 2021长安杯-virture
====================

虎符的代码量属实有点吓到了，我们来做一做去年长安杯的一道虚拟机题目缓一缓~

先打个预防针，题目关键词：**三十二元一次方程**

没找到main函数，那我们从start开始趴就。

```php
__int64 start()
{
  unk_411D80 = 0;
  sub_402450();
  return (unsigned int)sub_40115D();
}
```

跟进 sub\_402450()函数。不断跟进分析，一直跟进到sub\_401840函数。

很好 switch+while(1) vmre没跑了。结果我们兴高采烈的看到了30多个指令，2万多个字节的 opcode......

没关系，**只要思想不滑坡，办法总比困难多**。

先学习大佬把op\_code一条一条分开来分析

分析完之后发现，这题倒是没有那么丧心病狂，三十几个指令到头来只用到了十来个。

```php
0x01    加法运算
0x02    乘法运算
0x09    转移指令，相当于 mov reg ， Dword
0x0d    异或运算
0x12    转移指令，相当于 mov [addr] , reg
0x13    转移指令，相当于 mov reg ， Dword
0x15    字符输出，相当于 putchar()
0x16    字符输入，相当于 getchar()
0x17    没摸清楚，可以确定的是有个比较的功能
0x1b    退出，相当于 exit()
0x20    条件跳转，但在那种条件下跳转不明
0x21    不等于跳转，相当于 jne
```

分析一下这个题目的 逻辑 倒是很简单

```php
1. 输出字符串 “Please input the key:”
2. 接收32个字符的输入
3. 检测输入是否合法
4. 32 轮校验
```

最后看一下校验部分（节省篇幅，截取部分）:

```php
09  01  00  00  00  00        mov num_32 , Dword 0
13  00  00  00  00  00        load char flag[00]
09  02  3e  00  00  00        load char  3e >
02  00  02                    temp = 0x3e  *  flag[00]
01  01  00                    num_32 += temp 
13  00  01  00  00  00        load char flag[01]
09  02  21  00  00  00        load char  21 !
02  00  02                    temp = 0x21  *  flag[01]
01  01  00                    num_32 += temp 
13  00  02  00  00  00        load char flag[02]
09  02  33  00  00  00        load char  33 3
02  00  02                    temp = 0x33  *  flag[02]
01  01  00                    num_32 += temp 
13  00  03  00  00  00        load char flag[03]
```

可以发现，除了参数不同，剩余的部分都一样。整理出来发现是个32元一次方程，使用z3约束求解即可  
最后附上解题脚本

```python
from z3 import *
value1 = [
    0xac241d89,0x3c748602,0xd050dee3,0x6437ffd9,
    0x0d6f5ae8,0x8d08a075,0xbb43561f,0xa10913ca,
    0x0d647c66,0x61cb01dd,0x51f6cf38,0x86009a31,
    0xfb6afa06,0x26dfaeeb,0x76b24695,0xf3fde9a0,
    0xd8934cc7,0xf1aa539d,0xac6ddc1d,0xf0caaf80,
    0xf3401aff,0x980a0d4c,0x26e3a3bc,0x410f94d2,
    0x738c4f02,0xa39ebcfe,0x64399bab,0xc7ac872a,
    0xdc577d43,0xf82afcfd,0x993d28fc,0xb5aaf6b5]
value2 = [
    0xac268692,0x3c7639ab,0xd053e7d4,0x64358e07,
    0x0d6c5c0a,0x8d0a4298,0xbb405f60,0xa10a1755,
    0x0d66dd24,0x61c9e122,0x51f4aad8,0x86023671,
    0xfb681443,0x26dd5538,0x76b17016,0xf3ff3d06,
    0xd891a50f,0xf1a8e0e8,0xac6f3e04,0xf0c8014b,
    0xf342a73a,0x9808cfeb,0x26e1269a,0x410d7bec,
    0x738e895c,0xa39c7998,0x643b4245,0xc7ae4d47,
    0xdc55acf7,0xf82815ad,0x993fe1e1,0xb5a9c95c]
num_32 = []
for i in range(32):
    num_32.append(value1[i]^value2[i])
cha = ["v1","v2","v3","v4","v5","v6","v7","v8","v9","v10","v11","v12","v13","v14","v15","v16","v17","v18","v19","v20","v21","v22","v23","v24","v25","v26","v27","v28","v29","v30","v31","v32"]

tab = [
[62, 33, 51, 104, 42, 37, 80, 66, 46, 119, 63, 93, 40, 95, 69, 105, 54, 36, 93, 53, 66, 67, 62, 65, 80, 117, 50, 43, 36, 107, 108, 111],
[ 91, 72, 76, 37, 63, 111, 56, 51, 95, 54, 98, 125, 34, 49, 34, 94, 62, 65, 69, 98, 97, 109, 88, 61, 63, 58, 126, 66, 117, 51, 98, 84],
[ 105, 78, 82, 62, 119, 118, 88, 66, 97, 100, 86, 43, 124, 93, 70, 123, 116, 40, 93, 121, 95, 104, 86, 58, 122, 120, 101, 38, 123, 99, 49, 66],
[ 67, 34, 108, 65, 70, 37, 65, 38, 88, 54, 97, 62, 82, 51, 63, 59, 126, 33, 91, 47, 106, 36, 77, 35, 77, 114, 71, 57, 36, 111, 62, 62],
[ 83, 66, 38, 59, 124, 73, 120, 119, 82, 79, 36, 106, 74, 120, 124, 116, 71, 120, 43, 89, 61, 114, 124, 64, 97, 92, 71, 76, 43, 93, 38, 96],
[ 86, 77, 79, 65, 79, 47, 116, 35, 34, 91, 68, 54, 80, 42, 34, 95, 56, 105, 54, 126, 118, 60, 98, 119, 103, 121, 90, 42, 105, 100, 101, 87],
[ 70, 114, 91, 34, 116, 84, 123, 80, 124, 49, 41, 110, 107, 109, 99, 64, 74, 107, 88, 43, 105, 122, 60, 87, 68, 127, 83, 56, 75, 83, 48, 42],
[ 83, 122, 47, 116, 79, 73, 54, 57, 38, 34, 125, 52, 110, 105, 124, 80, 124, 92, 117, 98, 93, 89, 95, 87, 49, 125, 84, 36, 80, 74, 106, 117],
[ 97, 71, 81, 53, 97, 55, 54, 72, 45, 87, 113, 99, 126, 36, 47, 55, 41, 83, 106, 71, 60, 97, 74, 52, 82, 68, 71, 35, 85, 114, 39, 72],
[ 70, 109, 76, 82, 74, 105, 96, 94, 85, 74, 72, 75, 57, 106, 99, 80, 107, 36, 78, 95, 96, 43, 51, 124, 98, 99, 58, 107, 90, 61, 43, 71],
[ 52, 58, 46, 111, 78, 41, 39, 47, 105, 44, 43, 45, 37, 69, 125, 35, 104, 63, 34, 50, 117, 66, 89, 55, 56, 106, 83, 123, 72, 42, 62, 97],
[ 109, 103, 106, 80, 58, 45, 100, 51, 109, 76, 66, 103, 61, 48, 37, 93, 50, 45, 105, 97, 45, 77, 38, 114, 69, 121, 85, 77, 53, 55, 38, 37],
[ 90, 45, 47, 124, 64, 97, 84, 52, 83, 39, 100, 122, 101, 57, 83, 53, 82, 123, 122, 83, 102, 60, 61, 77, 109, 59, 123, 85, 54, 98, 101, 72],
[ 95, 102, 105, 116, 70, 49, 94, 114, 106, 63, 58, 37, 74, 113, 112, 64, 115, 35, 89, 64, 90, 98, 41, 94, 48, 119, 59, 81, 122, 99, 80, 124],
[ 33, 107, 67, 107, 48, 118, 81, 113, 58, 127, 125, 40, 123, 76, 117, 109, 66, 90, 107, 34, 95, 119, 76, 99, 117, 85, 117, 48, 47, 120, 70, 76],
[ 52, 90, 76, 55, 119, 103, 34, 34, 47, 54, 84, 93, 61, 48, 118, 115, 72, 56, 66, 116, 110, 119, 122, 85, 75, 67, 98, 104, 93, 51, 36, 110],
[ 32, 72, 111, 41, 78, 44, 122, 66, 46, 118, 42, 98, 112, 75, 113, 78, 105, 78, 124, 67, 124, 106, 86, 79, 38, 112, 51, 95, 108, 35, 36, 44],
[ 53, 73, 69, 102, 64, 53, 104, 100, 34, 72, 96, 69, 49, 122, 102, 39, 119, 57, 49, 42, 61, 121, 39, 84, 124, 61, 125, 115, 57, 47, 116, 47],
[ 110, 70, 62, 114, 84, 107, 46, 106, 99, 96, 74, 52, 121, 58, 127, 37, 106, 77, 116, 112, 118, 59, 50, 113, 56, 83, 74, 46, 42, 43, 50, 66],
[ 69, 71, 55, 77, 84, 67, 123, 98, 120, 124, 105, 122, 88, 57, 99, 39, 35, 67, 42, 43, 41, 92, 103, 46, 84, 38, 43, 83, 33, 87, 79, 39],
[ 41, 49, 91, 71, 122, 83, 69, 82, 45, 92, 94, 114, 50, 58, 48, 66, 109, 88, 62, 63, 121, 46, 41, 91, 107, 104, 125, 35, 119, 41, 71, 50],
[ 67, 93, 83, 62, 127, 91, 103, 37, 62, 34, 72, 111, 112, 33, 93, 119, 112, 81, 57, 112, 64, 73, 120, 36, 63, 53, 76, 48, 106, 111, 44, 122],
[ 116, 85, 120, 43, 81, 55, 115, 62, 102, 34, 38, 88, 36, 76, 35, 114, 97, 127, 60, 75, 73, 34, 52, 77, 42, 56, 93, 49, 76, 125, 56, 73],
[ 77, 111, 116, 34, 85, 42, 37, 38, 89, 65, 115, 121, 116, 103, 108, 106, 126, 86, 107, 125, 110, 48, 60, 87, 35, 53, 100, 101, 50, 117, 56, 65],
[ 103, 34, 77, 46, 44, 86, 124, 109, 77, 90, 50, 127, 40, 77, 39, 103, 84, 112, 89, 56, 96, 82, 36, 44, 88, 58, 72, 38, 89, 54, 123, 87],
[ 43, 48, 54, 45, 79, 88, 33, 54, 103, 100, 54, 49, 127, 108, 116, 87, 127, 121, 117, 93, 60, 101, 108, 50, 32, 36, 76, 55, 111, 61, 47, 121],
[ 113, 114, 113, 50, 122, 111, 120, 50, 122, 35, 102, 90, 89, 42, 62, 60, 86, 95, 43, 72, 114, 78, 82, 53, 70, 93, 118, 34, 87, 96, 62, 57],
[ 67, 104, 82, 72, 109, 117, 53, 39, 85, 97, 33, 82, 59, 39, 102, 37, 103, 39, 104, 71, 86, 43, 108, 123, 37, 125, 107, 56, 96, 119, 36, 108],
[ 91, 64, 43, 97, 46, 105, 49, 68, 68, 109, 33, 54, 90, 103, 117, 98, 52, 96, 32, 97, 87, 66, 72, 118, 66, 76, 87, 83, 53, 119, 90, 119],
[ 65, 53, 85, 84, 94, 82, 77, 70, 68, 97, 94, 86, 124, 54, 38, 52, 50, 124, 92, 64, 74, 85, 45, 94, 97, 110, 49, 123, 76, 56, 89, 120],
[ 109, 114, 33, 33, 76, 41, 61, 48, 41, 123, 65, 59, 85, 32, 127, 97, 98, 114, 87, 32, 67, 68, 108, 120, 116, 63, 109, 54, 92, 72, 72, 32],
[ 68, 84, 102, 97, 121, 127, 110, 126, 90, 109, 54, 60, 126, 86, 98, 92, 48, 103, 75, 124, 103, 119, 52, 84, 84, 91, 94, 44, 124, 76, 57, 99]
]

v1 = Int('v1')
v2 = Int('v2')
v3 = Int('v3')
v4 = Int('v4')
v5 = Int('v5')
v6 = Int('v6')
v7 = Int('v7')
v8 = Int('v8')
v9 = Int('v9')
v10 = Int('v10')
v11 = Int('v11')
v12 = Int('v12')
v13 = Int('v13')
v14 = Int('v14')
v15 = Int('v15')
v16 = Int('v16')
v17 = Int('v17')
v18 = Int('v18')
v19 = Int('v19')
v20 = Int('v20')
v21 = Int('v21')
v22 = Int('v22')
v23 = Int('v23')
v24 = Int('v24')
v25 = Int('v25')
v26 = Int('v26')
v27 = Int('v27')
v28 = Int('v28')
v29 = Int('v29')
v30 = Int('v30')
v31 = Int('v31')
v32 = Int('v32')

s = Solver()

s.add(62 * v1 + 33 * v2 + 51 * v3 + 104 * v4 + 42 * v5 + 37 * v6 + 80 * v7 + 66 * v8 + 46 * v9 + 119 * v10 + 63 * v11 + 93 * v12 + 40 * v13 + 95 * v14 + 69 * v15 + 105 * v16 + 54 * v17 + 36 * v18 + 93 * v19 + 53 * v20 + 66 * v21 + 67 * v22 + 62 * v23 + 65 * v24 + 80 * v25 + 117 * v26 + 50 * v27 + 43 * v28 + 36 * v29 + 107 * v30 + 108 * v31 + 111 * v32 == 170779)
s.add(91 * v1 + 72 * v2 + 76 * v3 + 37 * v4 + 63 * v5 + 111 * v6 + 56 * v7 + 51 * v8 + 95 * v9 + 54 * v10 + 98 * v11 + 125 * v12 + 34 * v13 + 49 * v14 + 34 * v15 + 94 * v16 + 62 * v17 + 65 * v18 + 69 * v19 + 98 * v20 + 97 * v21 + 109 * v22 + 88 * v23 + 61 * v24 + 63 * v25 + 58 * v26 + 126 * v27 + 66 * v28 + 117 * v29 + 51 * v30 + 98 * v31 + 84 * v32 == 180137)
s.add(105 * v1 + 78 * v2 + 82 * v3 + 62 * v4 + 119 * v5 + 118 * v6 + 88 * v7 + 66 * v8 + 97 * v9 + 100 * v10 + 86 * v11 + 43 * v12 + 124 * v13 + 93 * v14 + 70 * v15 + 123 * v16 + 116 * v17 + 40 * v18 + 93 * v19 + 121 * v20 + 95 * v21 + 104 * v22 + 86 * v23 + 58 * v24 + 122 * v25 + 120 * v26 + 101 * v27 + 38 * v28 + 123 * v29 + 99 * v30 + 49 * v31 + 66 * v32 == 211255)
s.add(67 * v1 + 34 * v2 + 108 * v3 + 65 * v4 + 70 * v5 + 37 * v6 + 65 * v7 + 38 * v8 + 88 * v9 + 54 * v10 + 97 * v11 + 62 * v12 + 82 * v13 + 51 * v14 + 63 * v15 + 59 * v16 + 126 * v17 + 33 * v18 + 91 * v19 + 47 * v20 + 106 * v21 + 36 * v22 + 77 * v23 + 35 * v24 + 77 * v25 + 114 * v26 + 71 * v27 + 57 * v28 + 36 * v29 + 111 * v30 + 62 * v31 + 62 * v32 == 160222)
s.add(83 * v1 + 66 * v2 + 38 * v3 + 59 * v4 + 124 * v5 + 73 * v6 + 120 * v7 + 119 * v8 + 82 * v9 + 79 * v10 + 36 * v11 + 106 * v12 + 74 * v13 + 120 * v14 + 124 * v15 + 116 * v16 + 71 * v17 + 120 * v18 + 43 * v19 + 89 * v20 + 61 * v21 + 114 * v22 + 124 * v23 + 64 * v24 + 97 * v25 + 92 * v26 + 71 * v27 + 76 * v28 + 43 * v29 + 93 * v30 + 38 * v31 + 96 * v32 == 198370)
s.add(86 * v1 + 77 * v2 + 79 * v3 + 65 * v4 + 79 * v5 + 47 * v6 + 116 * v7 + 35 * v8 + 34 * v9 + 91 * v10 + 68 * v11 + 54 * v12 + 80 * v13 + 42 * v14 + 34 * v15 + 95 * v16 + 56 * v17 + 105 * v18 + 54 * v19 + 126 * v20 + 118 * v21 + 60 * v22 + 98 * v23 + 119 * v24 + 103 * v25 + 121 * v26 + 90 * v27 + 42 * v28 + 105 * v29 + 100 * v30 + 101 * v31 + 87 * v32 == 189165)
s.add(70 * v1 + 114 * v2 + 91 * v3 + 34 * v4 + 116 * v5 + 84 * v6 + 123 * v7 + 80 * v8 + 124 * v9 + 49 * v10 + 41 * v11 + 110 * v12 + 107 * v13 + 109 * v14 + 99 * v15 + 64 * v16 + 74 * v17 + 107 * v18 + 88 * v19 + 43 * v20 + 105 * v21 + 122 * v22 + 60 * v23 + 87 * v24 + 68 * v25 + 127 * v26 + 83 * v27 + 56 * v28 + 75 * v29 + 83 * v30 + 48 * v31 + 42 * v32 == 199039)
s.add(83 * v1 + 122 * v2 + 47 * v3 + 116 * v4 + 79 * v5 + 73 * v6 + 54 * v7 + 57 * v8 + 38 * v9 + 34 * v10 + 125 * v11 + 52 * v12 + 110 * v13 + 105 * v14 + 124 * v15 + 80 * v16 + 124 * v17 + 92 * v18 + 117 * v19 + 98 * v20 + 93 * v21 + 89 * v22 + 95 * v23 + 87 * v24 + 49 * v25 + 125 * v26 + 84 * v27 + 36 * v28 + 80 * v29 + 74 * v30 + 106 * v31 + 117 * v32 == 197791)
s.add(97 * v1 + 71 * v2 + 81 * v3 + 53 * v4 + 97 * v5 + 55 * v6 + 54 * v7 + 72 * v8 + 45 * v9 + 87 * v10 + 113 * v11 + 99 * v12 + 126 * v13 + 36 * v14 + 47 * v15 + 55 * v16 + 41 * v17 + 83 * v18 + 106 * v19 + 71 * v20 + 60 * v21 + 97 * v22 + 74 * v23 + 52 * v24 + 82 * v25 + 68 * v26 + 71 * v27 + 35 * v28 + 85 * v29 + 114 * v30 + 39 * v31 + 72 * v32 == 172354)
s.add(70 * v1 + 109 * v2 + 76 * v3 + 82 * v4 + 74 * v5 + 105 * v6 + 96 * v7 + 94 * v8 + 85 * v9 + 74 * v10 + 72 * v11 + 75 * v12 + 57 * v13 + 106 * v14 + 99 * v15 + 80 * v16 + 107 * v17 + 36 * v18 + 78 * v19 + 95 * v20 + 96 * v21 + 43 * v22 + 51 * v23 + 124 * v24 + 98 * v25 + 99 * v26 + 58 * v27 + 107 * v28 + 90 * v29 + 61 * v30 + 43 * v31 + 71 * v32 == 188671)
s.add(52 * v1 + 58 * v2 + 46 * v3 + 111 * v4 + 78 * v5 + 41 * v6 + 39 * v7 + 47 * v8 + 105 * v9 + 44 * v10 + 43 * v11 + 45 * v12 + 37 * v13 + 69 * v14 + 125 * v15 + 35 * v16 + 104 * v17 + 63 * v18 + 34 * v19 + 50 * v20 + 117 * v21 + 66 * v22 + 89 * v23 + 55 * v24 + 56 * v25 + 106 * v26 + 83 * v27 + 123 * v28 + 72 * v29 + 42 * v30 + 62 * v31 + 97 * v32 == 157152)
s.add(109 * v1 + 103 * v2 + 106 * v3 + 80 * v4 + 58 * v5 + 45 * v6 + 100 * v7 + 51 * v8 + 109 * v9 + 76 * v10 + 66 * v11 + 103 * v12 + 61 * v13 + 48 * v14 + 37 * v15 + 93 * v16 + 50 * v17 + 45 * v18 + 105 * v19 + 97 * v20 + 45 * v21 + 77 * v22 + 38 * v23 + 114 * v24 + 69 * v25 + 121 * v26 + 85 * v27 + 77 * v28 + 53 * v29 + 55 * v30 + 38 * v31 + 37 * v32 == 175168)
s.add(90 * v1 + 45 * v2 + 47 * v3 + 124 * v4 + 64 * v5 + 97 * v6 + 84 * v7 + 52 * v8 + 83 * v9 + 39 * v10 + 100 * v11 + 122 * v12 + 101 * v13 + 57 * v14 + 83 * v15 + 53 * v16 + 82 * v17 + 123 * v18 + 122 * v19 + 83 * v20 + 102 * v21 + 60 * v22 + 61 * v23 + 77 * v24 + 109 * v25 + 59 * v26 + 123 * v27 + 85 * v28 + 54 * v29 + 98 * v30 + 101 * v31 + 72 * v32 == 192069)
s.add(95 * v1 + 102 * v2 + 105 * v3 + 116 * v4 + 70 * v5 + 49 * v6 + 94 * v7 + 114 * v8 + 106 * v9 + 63 * v10 + 58 * v11 + 37 * v12 + 74 * v13 + 113 * v14 + 112 * v15 + 64 * v16 + 115 * v17 + 35 * v18 + 89 * v19 + 64 * v20 + 90 * v21 + 98 * v22 + 41 * v23 + 94 * v24 + 48 * v25 + 119 * v26 + 59 * v27 + 81 * v28 + 122 * v29 + 99 * v30 + 80 * v31 + 124 * v32 == 195539)
s.add(33 * v1 + 107 * v2 + 67 * v3 + 107 * v4 + 48 * v5 + 118 * v6 + 81 * v7 + 113 * v8 + 58 * v9 + 127 * v10 + 125 * v11 + 40 * v12 + 123 * v13 + 76 * v14 + 117 * v15 + 109 * v16 + 66 * v17 + 90 * v18 + 107 * v19 + 34 * v20 + 95 * v21 + 119 * v22 + 76 * v23 + 99 * v24 + 117 * v25 + 85 * v26 + 117 * v27 + 48 * v28 + 47 * v29 + 120 * v30 + 70 * v31 + 76 * v32 == 210563)
s.add(52 * v1 + 90 * v2 + 76 * v3 + 55 * v4 + 119 * v5 + 103 * v6 + 34 * v7 + 34 * v8 + 47 * v9 + 54 * v10 + 84 * v11 + 93 * v12 + 61 * v13 + 48 * v14 + 118 * v15 + 115 * v16 + 72 * v17 + 56 * v18 + 66 * v19 + 116 * v20 + 110 * v21 + 119 * v22 + 122 * v23 + 85 * v24 + 75 * v25 + 67 * v26 + 98 * v27 + 104 * v28 + 93 * v29 + 51 * v30 + 36 * v31 + 110 * v32 == 185510)
s.add(32 * v1 + 72 * v2 + 111 * v3 + 41 * v4 + 78 * v5 + 44 * v6 + 122 * v7 + 66 * v8 + 46 * v9 + 118 * v10 + 42 * v11 + 98 * v12 + 112 * v13 + 75 * v14 + 113 * v15 + 78 * v16 + 105 * v17 + 78 * v18 + 124 * v19 + 67 * v20 + 124 * v21 + 106 * v22 + 86 * v23 + 79 * v24 + 38 * v25 + 112 * v26 + 51 * v27 + 95 * v28 + 108 * v29 + 35 * v30 + 36 * v31 + 44 * v32 == 190920)
s.add(53 * v1 + 73 * v2 + 69 * v3 + 102 * v4 + 64 * v5 + 53 * v6 + 104 * v7 + 100 * v8 + 34 * v9 + 72 * v10 + 96 * v11 + 69 * v12 + 49 * v13 + 122 * v14 + 102 * v15 + 39 * v16 + 119 * v17 + 57 * v18 + 49 * v19 + 42 * v20 + 61 * v21 + 121 * v22 + 39 * v23 + 84 * v24 + 124 * v25 + 61 * v26 + 125 * v27 + 115 * v28 + 57 * v29 + 47 * v30 + 116 * v31 + 47 * v32 == 177013)
s.add(110 * v1 + 70 * v2 + 62 * v3 + 114 * v4 + 84 * v5 + 107 * v6 + 46 * v7 + 106 * v8 + 99 * v9 + 96 * v10 + 74 * v11 + 52 * v12 + 121 * v13 + 58 * v14 + 127 * v15 + 37 * v16 + 106 * v17 + 77 * v18 + 116 * v19 + 112 * v20 + 118 * v21 + 59 * v22 + 50 * v23 + 113 * v24 + 56 * v25 + 83 * v26 + 74 * v27 + 46 * v28 + 42 * v29 + 43 * v30 + 50 * v31 + 66 * v32 == 188953)
s.add(69 * v1 + 71 * v2 + 55 * v3 + 77 * v4 + 84 * v5 + 67 * v6 + 123 * v7 + 98 * v8 + 120 * v9 + 124 * v10 + 105 * v11 + 122 * v12 + 88 * v13 + 57 * v14 + 99 * v15 + 39 * v16 + 35 * v17 + 67 * v18 + 42 * v19 + 43 * v20 + 41 * v21 + 92 * v22 + 103 * v23 + 46 * v24 + 84 * v25 + 38 * v26 + 43 * v27 + 83 * v28 + 33 * v29 + 87 * v30 + 79 * v31 + 39 * v32 == 175819)
s.add(41 * v1 + 49 * v2 + 91 * v3 + 71 * v4 + 122 * v5 + 83 * v6 + 69 * v7 + 82 * v8 + 45 * v9 + 92 * v10 + 94 * v11 + 114 * v12 + 50 * v13 + 58 * v14 + 48 * v15 + 66 * v16 + 109 * v17 + 88 * v18 + 62 * v19 + 63 * v20 + 121 * v21 + 46 * v22 + 41 * v23 + 91 * v24 + 107 * v25 + 104 * v26 + 125 * v27 + 35 * v28 + 119 * v29 + 41 * v30 + 71 * v31 + 50 * v32 == 179653)
s.add(67 * v1 + 93 * v2 + 83 * v3 + 62 * v4 + 127 * v5 + 91 * v6 + 103 * v7 + 37 * v8 + 62 * v9 + 34 * v10 + 72 * v11 + 111 * v12 + 112 * v13 + 33 * v14 + 93 * v15 + 119 * v16 + 112 * v17 + 81 * v18 + 57 * v19 + 112 * v20 + 64 * v21 + 73 * v22 + 120 * v23 + 36 * v24 + 63 * v25 + 53 * v26 + 76 * v27 + 48 * v28 + 106 * v29 + 111 * v30 + 44 * v31 + 122 * v32 == 180903)
s.add(116 * v1 + 85 * v2 + 120 * v3 + 43 * v4 + 81 * v5 + 55 * v6 + 115 * v7 + 62 * v8 + 102 * v9 + 34 * v10 + 38 * v11 + 88 * v12 + 36 * v13 + 76 * v14 + 35 * v15 + 114 * v16 + 97 * v17 + 127 * v18 + 60 * v19 + 75 * v20 + 73 * v21 + 34 * v22 + 52 * v23 + 77 * v24 + 42 * v25 + 56 * v26 + 93 * v27 + 49 * v28 + 76 * v29 + 125 * v30 + 56 * v31 + 73 * v32 == 165158)
s.add(77 * v1 + 111 * v2 + 116 * v3 + 34 * v4 + 85 * v5 + 42 * v6 + 37 * v7 + 38 * v8 + 89 * v9 + 65 * v10 + 115 * v11 + 121 * v12 + 116 * v13 + 103 * v14 + 108 * v15 + 106 * v16 + 126 * v17 + 86 * v18 + 107 * v19 + 125 * v20 + 110 * v21 + 48 * v22 + 60 * v23 + 87 * v24 + 35 * v25 + 53 * v26 + 100 * v27 + 101 * v28 + 50 * v29 + 117 * v30 + 56 * v31 + 65 * v32 == 192318)
s.add(103 * v1 + 34 * v2 + 77 * v3 + 46 * v4 + 44 * v5 + 86 * v6 + 124 * v7 + 109 * v8 + 77 * v9 + 90 * v10 + 50 * v11 + 127 * v12 + 40 * v13 + 77 * v14 + 39 * v15 + 103 * v16 + 84 * v17 + 112 * v18 + 89 * v19 + 56 * v20 + 96 * v21 + 82 * v22 + 36 * v23 + 44 * v24 + 88 * v25 + 58 * v26 + 72 * v27 + 38 * v28 + 89 * v29 + 54 * v30 + 123 * v31 + 87 * v32 == 181854)
s.add(43 * v1 + 48 * v2 + 54 * v3 + 45 * v4 + 79 * v5 + 88 * v6 + 33 * v7 + 54 * v8 + 103 * v9 + 100 * v10 + 54 * v11 + 49 * v12 + 127 * v13 + 108 * v14 + 116 * v15 + 87 * v16 + 127 * v17 + 121 * v18 + 117 * v19 + 93 * v20 + 60 * v21 + 101 * v22 + 108 * v23 + 50 * v24 + 32 * v25 + 36 * v26 + 76 * v27 + 55 * v28 + 111 * v29 + 61 * v30 + 47 * v31 + 121 * v32 == 181606)
s.add(113 * v1 + 114 * v2 + 113 * v3 + 50 * v4 + 122 * v5 + 111 * v6 + 120 * v7 + 50 * v8 + 122 * v9 + 35 * v10 + 102 * v11 + 90 * v12 + 89 * v13 + 42 * v14 + 62 * v15 + 60 * v16 + 86 * v17 + 95 * v18 + 43 * v19 + 72 * v20 + 114 * v21 + 78 * v22 + 82 * v23 + 53 * v24 + 70 * v25 + 93 * v26 + 118 * v27 + 34 * v28 + 87 * v29 + 96 * v30 + 62 * v31 + 57 * v32 == 186862)
s.add(67 * v1 + 104 * v2 + 82 * v3 + 72 * v4 + 109 * v5 + 117 * v6 + 53 * v7 + 39 * v8 + 85 * v9 + 97 * v10 + 33 * v11 + 82 * v12 + 59 * v13 + 39 * v14 + 102 * v15 + 37 * v16 + 103 * v17 + 39 * v18 + 104 * v19 + 71 * v20 + 86 * v21 + 43 * v22 + 108 * v23 + 123 * v24 + 37 * v25 + 125 * v26 + 107 * v27 + 56 * v28 + 96 * v29 + 119 * v30 + 36 * v31 + 108 * v32 == 182893)
s.add(91 * v1 + 64 * v2 + 43 * v3 + 97 * v4 + 46 * v5 + 105 * v6 + 49 * v7 + 68 * v8 + 68 * v9 + 109 * v10 + 33 * v11 + 54 * v12 + 90 * v13 + 103 * v14 + 117 * v15 + 98 * v16 + 52 * v17 + 96 * v18 + 32 * v19 + 97 * v20 + 87 * v21 + 66 * v22 + 72 * v23 + 118 * v24 + 66 * v25 + 76 * v26 + 87 * v27 + 83 * v28 + 53 * v29 + 119 * v30 + 90 * v31 + 119 * v32 == 184756)
s.add(65 * v1 + 53 * v2 + 85 * v3 + 84 * v4 + 94 * v5 + 82 * v6 + 77 * v7 + 70 * v8 + 68 * v9 + 97 * v10 + 94 * v11 + 86 * v12 + 124 * v13 + 54 * v14 + 38 * v15 + 52 * v16 + 50 * v17 + 124 * v18 + 92 * v19 + 64 * v20 + 74 * v21 + 85 * v22 + 45 * v23 + 94 * v24 + 97 * v25 + 110 * v26 + 49 * v27 + 123 * v28 + 76 * v29 + 56 * v30 + 89 * v31 + 120 * v32 == 190800)
s.add(109 * v1 + 114 * v2 + 33 * v3 + 33 * v4 + 76 * v5 + 41 * v6 + 61 * v7 + 48 * v8 + 41 * v9 + 123 * v10 + 65 * v11 + 59 * v12 + 85 * v13 + 32 * v14 + 127 * v15 + 97 * v16 + 98 * v17 + 114 * v18 + 87 * v19 + 32 * v20 + 67 * v21 + 68 * v22 + 108 * v23 + 120 * v24 + 116 * v25 + 63 * v26 + 109 * v27 + 54 * v28 + 92 * v29 + 72 * v30 + 72 * v31 + 32 * v32 == 182557)
s.add(68 * v1 + 84 * v2 + 102 * v3 + 97 * v4 + 121 * v5 + 127 * v6 + 110 * v7 + 126 * v8 + 90 * v9 + 109 * v10 + 54 * v11 + 60 * v12 + 126 * v13 + 86 * v14 + 98 * v15 + 92 * v16 + 48 * v17 + 103 * v18 + 75 * v19 + 124 * v20 + 103 * v21 + 119 * v22 + 52 * v23 + 84 * v24 + 84 * v25 + 91 * v26 + 94 * v27 + 44 * v28 + 124 * v29 + 76 * v30 + 57 * v31 + 99 * v32 == 212969)

sk = ""
if s.check() == sat:
    result = s.model()

sk = str(result)
else:
    print("Error")

dict = {}
sk = sk.replace(",", "").replace("]", ",").replace("[", "")

for i in sk.split("\n"):
    if i == "":
        continue
    temp = i.replace(",","").strip().split(" = ")
    dict[temp[0]] = temp[1]

print("flag{",end="")
for i in cha:
    print(chr(eval(dict[i])),end="")
print("}")
```

0x06 后记
=======

我只想说，不愧是堆栈结构的虚拟机逆向保护，够复杂，我喜欢。做了这么几个题目，总结出来的最重要的一点就是：不要被贸然增加的代码量所吓住，仔细分析抽丝剥茧，有可能你会发现实际用到的代码量不过表面展示的1/3。当然也有可能你会发现代码量真的很大，不过也没关系，vm类题目的思路还是很清晰的，只要沿着正确的道路坚定不移的走下去，铁杵也能磨成针。

0x07 参考文章
=========

[https://blog.csdn.net/m0\_46362499/article/details/106073746](https://blog.csdn.net/m0_46362499/article/details/106073746)

[https://blog.csdn.net/wlz\_lc\_4/article/details/104413282](https://blog.csdn.net/wlz_lc_4/article/details/104413282)

[https://blog.csdn.net/m0\_48218081/article/details/120386650](https://blog.csdn.net/m0_48218081/article/details/120386650)

[https://blog.csdn.net/wlz\_lc\_4/article/details/105734339](https://blog.csdn.net/wlz_lc_4/article/details/105734339)

[https://www.freesion.com/article/6242316998/#hagemweek4easy\_125](https://www.freesion.com/article/6242316998/#hagemweek4easy_125)

<https://blog.csdn.net/u012481172/article/details/50904574>

<https://bbs.pediy.com/thread-259116.htm>

<http://blog.iyzyi.com/index.php/archives/1252/>

发表于 2022-03-01 09:34:57
阅读 ( 5450 )
分类：其他

那CTF，那VMre，那些事（三）

0 条评论